AW: interior.color bei bedingter Formatierung
03.06.2005 15:13:35
Ramses
Hallo
mal einen Ansatz der noch ausbaufähig ist
'Auslesen der Farbe Bedingte Formatierung
' Von Bernd Strohhaecker
'Option expilcit
Sub TestCellColor()
MsgBox GetCellColor(ActiveCell), , "Meine Farbe ist:"
End Sub
Function GetCellColor(cell As Range) As Integer
Dim i
Dim myVal
Dim myColor As Integer
Dim done As Boolean
On Error Resume Next
Names("testname").Delete
On Error GoTo 0
Application.ReferenceStyle = xlR1C1
myVal = cell.Value
myColor = cell.Interior.ColorIndex
done = False
For i = 1 To cell.FormatConditions.count
With cell.FormatConditions.Item(i)
If .Type = 1 Then
Select Case .Operator
Case xlBetween
If myVal >= Evaluate(.Formula1) And myVal <= Evaluate(.Formula2) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlEqual
If myVal = Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlGreater
If myVal > Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlGreaterEqual
If myVal >= Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlLess
If myVal < Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlLessEqual
If myVal <= Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlNotBetween
If myVal < Evaluate(.Formula1) Or myVal > Evaluate(.Formula2) Then
myColor = .Interior.ColorIndex
done = True
End If
Case xlNotEqual
If myVal <> Evaluate(.Formula1) Then
myColor = .Interior.ColorIndex
done = True
End If
End Select
ElseIf .Type = 2 Then
Names.Add name:="testname", RefersToR1C1Local:=.Formula1
If Evaluate("testname") Then
myColor = .Interior.ColorIndex
done = True
End If
Names("testname").Delete
Else
MsgBox "Unbekannter Typ: " & .Type, , "PANIC: In
Function GetCellColor"
Exit Function
End If
End With
If done Then Exit For
Next
Application.ReferenceStyle = xlA1
GetCellColor = myColor
End Function
Gruss Rainer